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Advanced Math / Nonlinear functions Difficulty: Hard

Function f is defined by fx=x+6x+5x+1. Function g is defined by gx=fx-1. The graph of y=gx in the xy-plane has x-intercepts at a,0b,0, and c,0, where a , b , and c are distinct constants. What is the value of a + b + c ?

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Explanation

Choice B is correct. It's given that gx=fx-1. Since fx=x+6x+5x+1, it follows that fx-1=x-1+6x-1+5x-1+1. Combining like terms yields fx-1=x+5x+4x. Therefore, gx=xx+5x+4. The x-intercepts of a graph in the xy-plane are the points where y = 0 . The x-coordinates of the x-intercepts of the graph of y=gx in the xy-plane can be found by solving the equation 0=xx+5x+4. Applying the zero product property to this equation yields three equations:  x = 0 , x + 5 = 0 , and x + 4 = 0 . Solving each of these equations for x yields x = 0 , x = -5 , and x = -4 , respectively. Therefore, the x-intercepts of the graph of y=gx are 0,0-5,0, and -4,0. It follows that the values of a , b , and c are 0 , -5 , and -4 . Thus, the value of a + b + c is 0+-5+-4, which is equal to -9 .

Choice A is incorrect. This is the value of a + b + c if gx=fx+1.

Choice C is incorrect. This is the value of a + b + c - 1 if gx=x-6x-5x-1.

Choice D is incorrect. This is the value of a + b + c if fx=x-6x-5x-1.